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解決方案
  • <div class="wztuijian">
    <ul>
    {?php $query=urlencode('SELECT * FROM dr_1_article WHERE title LIKE '%不銹鋼%'');?}
    {sql sql='$query'}
    <li><a href={$t.url} target="_blank" title="{$t.title}">{$t.title}</a></li>
    {/sql}
    {$debug}
    </ul>
    </div>

    這樣也不對


    image

  • {php?$query=urlencode('SELECT?*?FROM?dr_1_article?WHERE?title?LIKE?"%不銹鋼%"');}
    滿意答案
    短信幣+1
  • @鄭中建:完美解決,太感謝了!!