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你要確定一下，就需要利用js來組裝跳轉了，類似這種

需要能看懂js語句才行

參考文檔：《搜索函數寫法 dr_search_url》

 {linkage code=pinpai pid=$params.pinpai}
    <a class="{if $t.id==$params.pinpai}on{/if}" href="{dr_search_url($params, 'pinpai', $t.id, 'news')}">{$t.name}</a>
 {/linkage}
 
 <a href="" class="btn">確定</a>

{linkage code=pinpai pid=$params.pinpai}
    <a class="{if $t.id==$params.pinpai}on{/if}" href="javascript:$('#aa').attr("href", '{dr_search_url($params, 'pinpai', $t.id, 'news')}');">{$t.name}</a>
 {/linkage}
 
 <a href="" id="aa" class="btn">確定</a>

這是很基礎的js啊

回復@優速開發工作室

不是很會js,能幫忙看看 就這兩個參數，怎么選中再確定篩選么，謝謝啦

<div id="screencon" class="con">

        <div id="subNavBox">
            <ul class="subNav">

                            <li class="icon titie">品牌</li>
                            <li id="screenAttribute9">
                                <a href="javascript:void(0)" class="on">不限</a>
                               {linkage code=pinpai pid=$params.pinpai}
                                <a class="{if $t.id==$params.pinpai}on{/if}" href="javascript:$('#aa').attr("href", '{dr_search_url($params, 'pinpai', $t.id, 'news')}');">{$t.name}</a>
                             {/linkage}
                            </li>
                            <li class="icon titie">價格區間</li>
                            <li id="screenAttribute10">
                                <a href="javascript:void(0)" class="on">不限</a>
                                    {linkage code=jiagequjian pid=$params.jiagequjian}
                                <a class="{if $t.id==$params.jiagequjian}on{/if}" href="{dr_search_url($params, 'jiagequjian', $t.id, 'news')}">{$t.name}</a>
                                {/linkage}
                            </li>

            </ul>
        </div>
        <div class="screenbtn">
            <a href="" class="btn">重置</a>
            <a  href="" id="aa" class="btn">確定</a>
        </div>
    </div>