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投訴 已解決 聯動菜單的偽靜態鏈接怎么寫 1 0
迅睿CMS版本:4.6.1 #共享欄目規則

聯動菜單。的偽靜態鏈接怎么整?最后一步了,求幫忙解決。

https://www.177kd.com/jingdongfang/


image

以下是我現在的規則

<?php

/**
 * URL解析規則
 * 例如:  114.html 對應 index.php?s=demo&c=show&id=114
 * 可以解析:  "114.html"  => 'index.php?s=demo&c=show&id=114',
 * 動態id解析:  "([0-9]+).html"  => 'index.php?s=demo&c=show&id=$1',
 */

return [
"tag" => "index.php?s=tag", // tag插件聚合首頁 
"tag\/(.+)\.html" => "index.php?s=tag&name=$1",  // tag插件
 "([A-za-z0-9 \-\_]+)" => "index.php?c=category&dir=$1",  //【共享欄目規則】模塊欄目列表(/{dirname}/)
    "([A-za-z0-9 \-\_]+)\/list_([0-9]+)_([0-9]+)\.html" => "index.php?c=category&dir=$1&page=$3",  //【共享欄目規則】模塊欄目列表(分頁)(/{dirname}/list_{id}_{page}.html)
 "([A-za-z0-9 \-\_]+)\/([0-9]+)_([0-9]+)\.html" => "index.php?c=show&id=$2&page=$3",  //【共享欄目規則】模塊內容頁(分頁)(/{dirname}/{id}_{page}.html)
  "([A-za-z0-9 \-\_]+)\/([0-9]+)\.html" => "index.php?c=show&id=$2",  //【共享欄目規則】模塊內容頁(/{dirname}/{id}.html)
   "([A-za-z0-9 \-\_]+)\/([A-za-z0-9 \-\_]+)_([0-9]+)\.html" => "index.php?c=category&dir=$2&page=$3",  //【頻道專用】模塊欄目列表(分頁)(/{otdirname}/{dirname}_{page}.html)
   "([A-za-z0-9 \-\_]+)\/([A-za-z0-9 \-\_]+)\.html" => "index.php?c=category&dir=$2",  //【頻道專用】模塊欄目列表(/{otdirname}/{dirname}.html)

 "tag\/p([0-9]+).html" => "index.php?s=tag&page=$1", // tag插件聚合首頁分頁
 'sitemap.xml' => 'index.php?s=sitemap&c=home&m=xml&page=998', // sitemap.xml地圖規則
 'sitemap.txt' => 'index.php?s=sitemap&page=999', // sitemap.txt地圖規則
 'tag.txt' => 'index.php?s=sitemap&c=home&m=tag&page=998', // tag.txt地圖規則
 "tag\/(.+)\-([0-9]+)\.html" => "index.php?s=tag&name=$1&page=$2",  // tag插件分頁
    
    "([a-z]+)\/search\.html" => "index.php?s=$1&c=search",  //【共享模塊搜索規則】模塊搜索頁({modname}/search.html)
    "([a-z]+)\/(.+)\.html" => "index.php?s=$1&c=search&rewrite=$2",  //【共享模塊搜索規則】模塊搜索頁(分頁)({modname}/{param}.html)
];

解決方案