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解決問題：如何防止別人通過ID來采集網站？

1、創建一個fcaiji的字段，以下是代碼

{"name":"防采集","fieldname":"fcaiji","fieldtype":"Text","isedit":"1","ismain":"1","issystem":"0","ismember":"1","issearch":"0","disabled":"0","setting":{"option":{"fieldtype":"CHAR","fieldlength":"4","value":"","width":"","css":""},"validate":{"xss":"1","required":"0","pattern":"","errortips":"","check":"","filter":"user_gl_caiji","tips":"","formattr":""},"is_right":"0"},"displayorder":"0"}

2、在custom.php文件中放出以下代碼

function my_cjurl($data) {

$url=$data['fcaiji'].$data['id'].'.html';

return $url;

}

function my_gl_caiji($value, $data = [], $old = []) {

if(empty($value)){

$characters = 'abcdefghijklmnopqrstuvwxyz';

$shuffledCharacters = str_shuffle($characters);

$value = substr($shuffledCharacters, 0, 4);

}

return $value; // 返回的數據一定要是字符串格式！！！

}

3、創建URL規則，這里只有獨立模塊的

{"id":"4","type":"1","name":"防采集","value":"{\"module\":\"{modname}.html\",\"list\":\"{modname}/{dirname}/\",\"list_page\":\"{modname}/{dirname}/{page}/\",\"show\":\"{modname}/{my_cjurl($data)}\",\"show_page\":\"{modname}/{id}_{page}.html\",\"search\":\"{modname}/sch.html\",\"search_page\":\"{modname}/sch-{param}.html\",\"catjoin\":\"/\"}"}

4、在rewrite.php中用如下規則

"([a-z]+)\/([a-z]+)([0-9]+)\.html" => "index.php?s=$1&c=show&fcaiji=$2&id=$3",

5、在list.html中用上maxlimit=100的參數

6、在hooks.php中用上如下參數

\Phpcmf\Hooks::app_on('appname', 'module_search_data', function($data) {

$page=$_GET['page'];

if($page>5){

XR_C()->goto_404_page(dr_lang('該分頁不存在'));

}

});

\Phpcmf\Hooks::app_on('appname', 'module_show', function($data) {

$fcaiji=$_GET['fcaiji'];

if($data['fcaiji']&&$fcaiji!==$data['fcaiji']){

XR_C()->goto_404_page(dr_lang('內容不存在！'));

}

return dr_return_data(1, '', $data);

});